Find The Measure Of Each Angle

Help me find the size of each corner.

In a triangle, the first angle is twice the second. The dimension of the third corner is 64 degrees greater than the dimension of the second corner. Use the fact that the sum of the dimensions of the three angles in a triangle is 180 degrees Find the dimensions of each angle.

Let X be measured from another angle.

The angles measure 2x, x and x + 64.

Add 180, solve x and find other angles.

23.2 + 23.2 * 2 + 23.2 * 2 + 64.

=>.

Let the second angle be x, then the first becomes 2x and the third is a (x + 64)

Then

2x + x + (x + 64) = 180.

4x = 116.

x = 29 => Monday.

2x = 58 => 1 to.

x + 64 = 93 => from 3rd.

Find The Measure Of Each Angle

Help me find the size of each corner.
In a triangle, the first angle is twice the second. The dimension of the third corner is 64 degrees greater than the dimension of the second corner. Use the fact that the sum of the dimensions of three angles in a triangle is 180 degrees to find the dimensions of each angle.
Let x be the measure of the second angle.
The angles measure 2x, x and x + 64.
Add, solve 180, find x and find other angles.
=>
Let 2nd angle be x, then 1st is 2x and third is a (x + 64)
Then
2x + x + (x + 64) = 180
4x = 116
x = 29 => Monday
2x = 58 => from 1st
x + 64 = 93 => from the third