Cr2 So4 3
Oxidation No. Cr2 (SO4) 3? 3
Cr =?
S =?
Is =?
I know there is Oxygen 2 but can anyone tell me where to go from there? I'm sure it will increase to 0.
Divide the mixture into cations and anions.
2Cr 3+ and 3 (SO4) 2
SO4 2
S + 4 (2) = 2
S8 = 2
S = 6
To check the answer:
Cr2 (SO4) 3
= 2 (3) + 3 [6 + 4 (2)]
= 6 + (6)
= 0
CrSo4 3
Cr2 So4 3
The total charge of the sule is 2.3 sule so its total charge is 6. Cr2 must have a total charge of +6 for equilibrium (since the charge on the molecule is 0). In this case, the oxidation number of each Cr is +3.
Since the charge of the solar is 2 and the charge of each oxygen is 2, the oxidation number of the sulr can be ascertained by detecting the charge of the sulr that it must be a molecule to hold the charge of 2. 4 The total number of oxygen is 8, + 6 must be the oxidation number.
When the oxidation number decreases, it means that you need electrons. That is, n negatively charged electrons reduce the number of oxidation states. Therefore, it is reduced because it needs electrons. Since it is being reduced, it must be an oxidizing agent.
