Battery Operated Bottle Warmer
Physics: Electricity? ۔
The 10.0V battery bottle heats 60.0 g glass, 2.30 ± • 10 2 g baby food and 2.50 • 10 2 g aluminum 25.0 ° C to 85.0 ° C. (Note: Please note that the specific temperature formula is equal to the specific water temperature.)
a.) How much does the battery charge (in C)?
(B)
If the formula takes 4.00 minutes to heat up, how many electrons flow per second?
________ electrons
of the)
Specific heat gl: 750 J / kg K
Specific water temperature: 4181 J / kg K.
Aluminum specific temperature: 921 J / kg K.
Convert each gram into a joule that will be absorbed by each.
Example calculation for gl:
60 g * (1 kg / 1000 g) * (750 J / kg) * (85 kg 25 kg) = 2700 J
For water: 57700 J.
For aluminum: 13,800J.
The energy absorbed by each part is the energy emitted by the battery, so the sum of the energy absorbed is the total energy of the battery.
2700J + 57700J + 13800J = 74200J.
Now we use the definition of Joule: J = C * V.
As we knew our volts and found our joules, we decided on Columbus.
74200J = C * 10V.
C = 7420 c.
B)
Convert Columbus to Electron
7420C * (1 and / 1.6022E19 C) = 4.63 E22 electrons.
Convert minutes to seconds.
4 minutes * (60 seconds / 1 minute) = 240 seconds.
Electron rate: 4.63E22 e / 240s = 1.93E20 electrons / s.
We heat 3 items from one temperature to another.
Using the formula E = m * c * deltaT, determine the heat energy for each of these objects, where c is the specific heat capacity of each object.
Then combine these three energies together. All this energy is provided by the battery, without any damage.
For milk c is 4.18 J / (Â g Cg), then E n = (2.30Â - 10 2 g) (4.18 JÂ ° C 1g 1) (60Â ° C) = 57680 J
Aluminum E = (2.50 - 10 2 g) (0.897 J ° C 1 g 1) (60 ° C) = 13,460 J
Since there is no c for gl, we have to find one. Use this value if you have a row at the end of the book.
c (gl) = 0.75 J / (g ° C), approx
E = 2700J.
, 73,840 years.
If a source has a voltage of V and the load is transferred to Q (C), then the internal energy is J = V * Q.
73840 J = (10 V) (Q)
Q = 7.38 - 10 3 C.
B)
7380 C / 240 s = 308 C / s = 30.77 A.
Since each C represents 6.24 × 10 18 electrons, multiply.
1.92 × 10 20 i / s.
Battery Operated Bottle Warmer
Battery Operated Bottle Warmer
Physics: Electricity? 3
The 10.0 V battery bottle warmer heats 60.0 grams of glass, 2.30 ± • 10 2 grams of baby food and 2.50 • 10 2 g of aluminum from 25.0 ° C to 85.0 ° C. (Note: Please note that the specific heat formula is equal to the specific temperature of water.)
a) How much charge does the battery transfer (in C)?
(B)
If the formula takes 4.00 minutes to heat up, how many electrons are flowing per second?
________ electrons
of the)
Specific heat gl: 750 J / kg K
Specific water temperature: 4181 J / kg K.
Aluminum specific temperature: 921 J / kg K.
Convert each gram into joules that will be absorbed by each.
Example of gl calculation:
60 g * (1 kg / 1000 g) * (750 J / kg K) * (85 K 25 K) = 2700 J
For water: 57700 J.
For aluminum: 13,800 J.
The energy absorbed from each part is the energy emitted by the battery, so the sum of the energy absorbed is the total energy of the battery.
2700J + 57700J + 13800J = 74200J
Now we use the definition of Joule: J = C * V
As we knew our volts and searched for our joules, we decided on Columbus.
74200 J = C * 10 V
C = 7420 C
B)
Convert coulombs to electrons.
7420C * (1 and / 1.6022E19 C) = 4.63 E22 electrons
Convert minutes to seconds.
4 minutes * (60 seconds / 1 minute) = 240 seconds
Electron rate: 4.63E22 e / 240s = 1.93E20 electrons / s
We heat 3 items from one temperature to another.
Using the formula E = m * c * deltaT, determine the heat energy required for each of these objects, where c is the specific heat capacity of each object.
Then combine these three energies together. This is all energy that is supplied by the battery, without any damage.
For milk c is 4.18 J / (Â g Cg), then E n = (2.30Â - 10 2 g) (4.18 JÂ ° C 1g 1) (60Â ° C) = 57680 J
Aluminum E = (2.50 - 10 2 g) (0.897 J ° C 1 g 1) (60 ° C) = 13,460 J
Since there is no c for gl, we have to find one. Use this value if you have a row at the end of the book.
c (gl) = 0.75 J / (g ° C), approx
E = 2700 J.
~ 73,840 years.
If a source has a voltage of V and it transfers the load to Q (in C), then the internal energy is J = V * Q.
73840 J = (10 V) (Q)
Q = 7.38 - 10 3 C
B)
7380 C / 240 s = 308 C / s = 30.77 A
Since each C represents 6.24 × 10 18 electrons, multiply.
1.92 × 10 20 i / s
