Analysis Of A Compound Containing Chlorine And Lead
Tests for chlorine and lead compounds showed that the compound was 59.37% lead. ? 3
The molarity of the mixture is 349.0 g / mol. What is the experimental formula for chloride? (Write your answer in CO2 to CO2 format).
What is the experimental formula?
Assuming 59.37%, you mean m.
So you know that 59.37% * 349g = 207.2g is the lead.
Divide the molar by the lead and you will get 1 mole of lead.
The remainder (349.207.2 = 141.8) is chlorine and is divided by m molar chlorine to obtain 4 ■■■■■ of Cl.
The experimental formula is PbCl4.
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